Find the m < ABC , need help ASAP

Given :-
AB = AC
Then :-
This triangle is an isosceles triangle .
Let x be the value of ∠CAB . Then, ∠ABC will also have the same value as ∠CAB , since∠CAB and∠ABC are both the opposite base angles of an isosceles triangle .
An equation to find ∠ABC and ∠CAB :-
[tex] = x + x + 60 = 180[/tex]
[tex] = 2x + 60 = 180[/tex]
[tex] = 2x = 180 - 60[/tex]
[tex] = 2x = 120[/tex]
[tex] = x = \frac{120}{2} [/tex]
[tex] = x = 60[/tex]
Which means that the measure of ∠ABC and ∠CAB both are equal to 60°, and this triangle is an equilateral triangle.
Therefore :-
[tex]\color{olive}\bold{m∠ABC\color{hotpink} = 60°}[/tex]
[tex]\large{\underline{\underline{\red{\tt{\purple{\leadsto } GiveN\:\: Figure:-}}}}}[/tex]
[tex]\setlength{\unitlength}{1 cm}\begin{picture}(12,8)\put(0,0){\line(1,0){4}}\put(4,0){\line(-1,2){2}}\put(2,4){\line( -1, - 2){2}}\put(2,4.2){$\bf B $}\put(0, - 0.3){$\bf A $}\put(4, - 0.3){$\bf C $}\put(2,0.2){\line(0,-1){0.4}}\put(0.8,2){\line(1,-2){0.2}}\put(3.3,0.1){$\sf 60^{\circ}$}\end{picture}[/tex]
[tex]\large{\underline{\underline{\red{\tt{\purple{\leadsto } AnsweR:-}}}}}[/tex]
It is given that AB = AC . Since two sides of the triangle are equal , hence it must be an isosceles triangle .
And we know that in an isosceles triangle two base angles are equal . So ∠ABC = ∠ ACB = 60° .