Answer:
a = - 1 [m/s²]
Explanation:
To solve this problem we must use the following equation of kinematics.
[tex]v_{f} = v_{o} +(a*t)[/tex]
where:
Vf = final velocity = 0 (velocity at 10 seconds)
Vo = initial velocity = 4 [m/s]
a = desacceleration [m/s²]
t = time = 4 [s]
From the graph, we can deduce that between the second 10 and the second 6 there are (10-6) = 4 seconds difference.
In the second 6, the velocity is 4 [m/s]
0 = 4 + (a*4)
4*a = -4
a = - 1 [m/s²]
