Question

what is the larger number if sum of the number is 78 and their product is 1352​

Answer 1

Answer:

26 and 52

26+52=78

26*52=1352

Explanation:

         \ ab /

        a \ / b

        /a+b\

Pretend the slashes form an x.

We know ab=1352, and a+b=78.

First, we can find the factors of 1352. The factors are 1, 2, 4, 8, 13, 26, 52, 104, 169, 338, 676, and 1352.

Or:

1*1352

2*676

4*338

8*169

13*104

26*52

52*26

104*13

169*8

338*4

676*2

1352*1

Next, find two factors that equal 78.

1+1352=1353

2+676=678

4+338=342

8+169=177

13+104=117

26+52=78

26+52=78, and 26*52=1352

So, a=26, and b=52. Since both numbers are positive, order doesn't matter.

Answer 2

The larger Number of the two values which conforms to the rules given is 52.

Let the numbers be a and b

The sum :

a + b = 78

The product :

a × b = 1352

Next, we obtain the factors of 1352:

The factors of 1352 are :

1, 2, 4, 8, 13, 26, 52, 104, 169, 338, 676, 1352

The sum of any two numbers from the factors should give 78 ;

Factors greater 78 cannot give a sum of 78 ;

Hence, we Try lesser values :

13 + 26 = 39

52 + 26 = 78

Hence, the values are 52 and 26

The larger number is thus 52 ; since 52 > 26

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