Question

1. A ball rolls down a hill with a constant acceleration of 2.5 m/s^2. The ball
starts at rest and travels for 4.0 seconds before it hits a wall and stops.
How far did the ball travel before it stopped? *
a. 8.0 m
b. 12 m
c. 16 m
O d. 20 m

Answer 1

Answer:

D 20m

Explanation:

Distance = $ut + \frac{1}{2} at^{2}$

where u = initial velocity, t  = time taken, a = acceleration

Since, the ball starts at rest, initial velocity = 0 m/s

Time = 4.0 seconds  (given)

Acceleration = 2.5 m/s^2  (given)

So, distance = 0*4 + (0.5 * 2.5 *4^2) = 20m