Question

An object is moving with an initial velocity of 5.5 m/s. It is then subject to an acceleration of 2.5 m/s² for 11 s. How far will it have traveled during the time of its acceleration? OML HELP

Answer 1

Answer: 211.75m

Explanation:

Listing everything the question gives you:

Vi = 5.5

a = 2.5

t = 11

ΔX = ?

Then pick a kinematic equation to solve for the missing variable

I used this one: Δx = Vit + $\frac{1}{2} at^2$

When you plug in all ur variables you get Δx = 211.75m