Answer:
28.3 m/s 45° below horizontal
Explanation:
Given in the y direction:
Δy = -20 m
v₀ = 0 m/s
a = -10 m/s²
Find: v
v² = v₀² + 2aΔy
v² = (0 m/s)² + 2 (-10 m/s²) (-20 m)
v = -20 m/s
In the x direction, acceleration is 0, so v = v₀ = 20 m/s.
The magnitude is found with Pythagorean theorem:
v² = (20 m/s)² + (-20 m/s)²
v = 28.3 m/s
The direction is found with trig:
θ = atan(-20 m/s / 20 m/s)
θ = -45°
