Question

A 16 L sample of gas is under a pressure of 6.0 atm. What will be the pressure of the gas when the volume increases to 22 L? Assume the temperature is held constant.

Answer 1

Answer:

The answer is 4.36 atm

Explanation:

The new pressure can be found by using the formula for Boyle's law which is

$P_1V_1 = P_2V_2$

Since we are finding the new pressure

$P_2 = \frac{P_1V_1}{V_2}$

From the question we have

$P_2 = \frac{1 6\times6 }{22} = \frac{96}{22} \\ = 4.363636...$

We have the final answer as

4.36 atm

Hope this helps you

Answer 2

Answer:

Let's start off with identifying our known and unknown variables.

The first volume we have is 12.0 L, the first pressure is 28.0 atm, and the second pressure is 9.70 atm. Our only unknown is the second volume.

We can obtain the answer using Boyle's Law which shows that there is an inverse relationship between pressure and volume as long as the temperature and number of moles remain constant.

The equation we use is  

P

1

V

1

=

P

2

V

2

where the numbers 1 and 2 represent the first and second conditions. All we have to do is rearrange the equation to solve for the volume.

We do this by dividing both sides by  

P

2

in order to get  

V

2

by itself like so:

P

1

V

1

 

÷

P

2

=  

V

2

Now all we do is plug and chug!

(28.0  

a

t

m

)) (12.0 L)  

÷

(9.70  

a

t

m

)) = 34.6 L

Boyle's Law Practice Problems

Explanation: