Question

If a 3.1g ring is heated using 10.0 J, its temperature rises 19.7°C. Calculate
the specific heat capacity of the ring.

Answer 1

Answer:

Since 10 J / 4.19 J /cal = 2.39 cal     is the heat absorbed by the ring

Q = Cs * m * (T2 - T1)      heat absorbed by ring

Cs = 2.39 cal / (3.1 g * 19.7 deg C) = .039 cal / (gm deg C)