Answer:
[tex]d = 2\sqrt{10}[/tex]
Step-by-step explanation:
(4, 3) (6, 9)
[tex]d=\sqrt{(x_2-x_1)^{2} +(y_2-y_1)^{2} }[/tex]
[tex]d=\sqrt{(6-4)^{2} +(9-3)^{2} }[/tex]
[tex]d=\sqrt{(2)^{2} +(6)^{2} }[/tex]
[tex]d=\sqrt{(4 +36)}[/tex]
[tex]d=\sqrt{40} = 2\sqrt{10}[/tex]
