Answer:
The account balance after three years is approximately $580.38
Step-by-step explanation:
The given parameters are;
The principal amount deposited, [tex]P_0[/tex] = $500
The interest rate on the account, r = 5% = 0.05
The rate of interest, k = Quarterly = 4
The time of the investment N = 3 years
The formula for the account balance, [tex]P_N[/tex], after a given N time period is given as follows;
[tex]P_N = P_0 \times \left (1 + \dfrac{r}{k} \right )^{n \times k}[/tex]
Substituting the values, gives;
[tex]P_3 =500 \times \left (1 + \dfrac{0.05}{4} \right )^{3 \times 4} = 580.38[/tex]
The account balance after three years ≈ $580.38.