Question

Consider a 16 GByte memory (16G locations each holding one byte). What is the number of address lines (N)?

Answer 1

Answer:

Number of address lines (N) = 34

Explanation:

16G locations each holding 1 byte

           byte

1g    1 - 1 - 1 - 1 - 1 - 1 - 1 - 1

2g

3g

.

.

.

16g

note that; 1 byte = 8 bit

therefore for 16G location, address line(N) will be:

since it is known that $2^{N}$ = 16G   ,and   1 gigabyte = $2^{30}$ byte

∴ 16G = 16 × $2^{30}$

          = 2⁴ × 2³⁰

          = 2³⁴

since $2^{N}$ = 16G

∴    $2^{N}$ = 2³⁴

N = 34