A gas was trapped in a container containing 10mL of air at a pressure of 1.0 atm. What will be the new volume,if the pressure is changed to 5 atm at the same temperature?​

Respuesta :

Answer:

The answer is 2 mL

Explanation:

The volume of the gas can be found by using the formula for Boyle's law

[tex]P_1V_1 = P_2V_2[/tex]

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we are finding the new volume

[tex]V_2 = \frac{P_1V_1}{P_2} \\[/tex]

We have

[tex]V_2 = \frac{10 \times 1}{5} = \frac{10}{5} \\ [/tex]

We have the final answer as

2 mL

Hope this helps you

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