Question

If 2000 ft³ of air is crossing an evaporator coil and is cooled from 80°F to 60°F, what would be the volume of air in ft³ exiting the evaporator coil?

Answer 1

Given :

If 2000 ft³ of air is crossing an evaporator coil and is cooled from 80°F to 60°F.

To Find :

The volume of air in ft³ exiting the evaporator coil.

Solution :

We know, relation between initial and final temperature and volume is given by :

$\dfrac{V_1}{V_2}=\dfrac{T_1}{T_2}$

Here, temperature is in Kelvin .

We know, Kelvin temperature is given by :

$K=(F-32)\times \dfrac{5}{9} + 273$

Putting F = 60° F,

$K=(60-32)\times \dfrac{5}{9} + 273\\\\K = 288.56\ K$

Putting F = 80° F,

$K=(80-32)\times \dfrac{5}{9} + 273\\\\K = 299.67\ K$

Putting all values, we get :

$\dfrac{V_1}{2000}=\dfrac{60}{80}\\\\V_1=\dfrac{60\times 2000}{80}\ ft^3\\\\V_1=1500\ ft^3$

Hence, this is the required solution.