Question

) Chromate/Dichromate Equilibrium. Yellow chromate ion reacts with hydrogen ion to form (by condensation and loss of H2O) the orange dichromate ion:

Answer 1

Answer:

Explanation:

The Chromite ore is used for the production of Chromate/dichromate formation.

$4FeCr2O4 + 8Na2CrO4+7O2$ →$8NaCrO4 +2Fe2O3 +8CO2\\yellow$

so$Na2CrO4$ is called Chromite ore which is of yellow color.

$Na2CrO4 +2H^+$ → $Na2CrO4 +2Na^+ +H2O$

                                $Orange$

so when sodium chromate is reacted with hydrogen ion it forms sodium dichromate which is of orange color

Now

$Na2Cr2O7+2KCl$→$K2Cr2O7 + NaCl$

The chromate and dichromate are interconvertible in aqueous solution depending upon the PH of solution

Acid medium: $Cr2O4^2-$ $2H^+$→$Cr2O7^2-$$+H2O$

Base:$Cr2O7^2- +2OH^-$→  $CrO4^2- +H2O$

Hence Chromate and dichromate are interconvertible and hold and equilibrium.