Question

How many different passwords of length 10 can be formed using 2 letters (A,...,Z) and 8 digits (0,1,...,9)

Answer 1

Answer: 67600000000

Step-by-step explanation:

The password has length 10 characters using 2 letters (A,...,Z) and 8 digits (0,1,...,9).

Total letters = 26

Total digits = 10

If repetition is allowed, then the number of different passwords of length 10 can be formed = $(26)^2\times (10)^8=67600000000$

Hence, the different passwords of length 10 can be formed = 67600000000