What is the percent m/m concentration of an aqueous solution of sodium nitrate in which there are 24.34 grams of solute in 138.87 grams of solvent

Respuesta :

Answer:

14.9%m/m

Explanation:

The percent m/m concentration of a solution (%m/m) indicates the grams of solute there are in 100 g of solution. It can be calculated as follows:

[tex]%m/m= \frac{mass of solute (g)}{mass of solution(g)} x 100[/tex]%m/m= mass of solute(g)/mass of solution(g) x 100

As the solution is composed by solute + solvent, the mathematical expression can be transformed in:

[tex]%m/m= \frac{mass of solute (g)}{mass of solution(g)} x 100[/tex]%m/m= mass of solute(g)/(mass of solute + mass of solvent (g) )x 100

         = 24.34 g[tex]%m/m= \frac{mass of solute (g)}{mass of solution(g)} x 100[/tex]/(24.34 g + 138.87 g) x 100

         = 24.34 g/(163.21 g) x 100

         = 14.9%

[tex]%m/m= \frac{mass of solute (g)}{mass of solution} x 100 = \frac{mass of solute (g)}{mass of solute (g) + mass of solvent (g)}[/tex]

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