Question

The amount of soda in a 16-ounce can is normally distributed with a mean of 16 ounces and a standard deviation of 0.20 ounce. What percentage of these cans will have less than 15.6 ounces

Answer 1

Answer: The percentage of these cans will have less than 15.6 ounces = 2.28%

Step-by-step explanation:

Let x = amount of soda in a 16-ounce can which  is normally distributed.

$\mu=16\text{ ounces},\ \ \ \ \sigma=0.20\text{ ounces}$

The probability that cans will have less than 15.6 ounces:

$P(X<15.6)=P(\dfrac{X-\mu}{\sigma}<\dfrac{15.6-16}{0.20})\\\\=P(z<-2)=1-P(Z<2)\\\\=1-0.9772\ \ \ [\text{By p-value table}]\\\\=0.0228=2.28\%$

Hence, the percentage of these cans will have less than 15.6 ounces = 2.28%