Answer:
12.898A
Explanation:
The formula for calculating the magnetic field in the loop bus expressed as;
B = Iμ0/2r
Given
Diameter d = 0.60cm
Radius r = d/2 = 0.30cm
r = 0.0030m
Permittivity of free space μ0 = 4π×10^-7
Magnetic field strength B = 2.7×10^-3T
Substitute into the formula and get I
2.7×10^-3 = 4π×10^-7I/2(0.0030)
2.7×10^-3 = 4π×10^-7I/0.0060
Cross multiply
2.7×10^-3 × 6.0×10^-3 = 4π×10^-7I
16.2×10^-6 = 4π×10^-7I
I = 16.2×10^-6/4π×10^-7
I = 16.2×10^-6/4(3.14)×10^-7
I = 16.2×10^-6/12.56×10^-7
I = 1.2898×10^{-6+7}
I = 1.2898×10
I = 12.898A
Hence the current in the loop is 12.898A
