Question

What is the net work, in joules, required to stop a crate of mass 64.5 kg that is moving at a speed of 1.26 m/s

Answer 1

Answer:

51.2Joules

Explanation:

Work done = Force × distance

Force = mg = 64.5×9.81

Force = 632.745N

Next is to get the distance using the equation of motion

v² = u²+2gS

1.26² = 0+2(9.81)S

1.5876 = 19.62S

S = 1.5876/19.62

S = 0.0809m

Get the work done:

Work done = F×S

Work done = 632.745×0.0809

Work done = 51.2Joules

Hence the net work done in Joules is 51.2Joules

Answer 2

The net work done required to stop a crate will be "51.2 Joules".

Force and Mass

According to the question,

Mass, m = 64.5 kg

Speed, v = 1.26 m/s

Acceleration due to gravity, g = 9.8

We know,

The force, F = mg

By substituting the values,

                    = 64.5 × 9.8

                    = 632.745 N

By using Equation of motion,

→       v² = u² + 2gS

 (1.26)² = 0 + 2(9.81) S

1.5876 = 19.62 S

         S = $\frac{1.5876}{19.62}$

            = 0.0809 m  

hence,

The work done (W) will be:

= F × S

= 632.745 × 0.0809

= 51.2 Joules

Thus the above response above is correct.

Find out more information about mass here:

https://brainly.com/question/25545050