Question

Write an expression that will cause the following code to print "Equal" if the value of sensorReading is "close enough" to targetValue. Otherwise, print "Not equal". Hint: Use epsilon value 0.0001. Ex: If targetValue is 0.3333 and sensorReading is (1.0/3.0), output is: Equal

Answer 1

Answer:

The expression that does the comparison is:

if abs(targetValue - sensorReading) < 0.0001:

See explanation section for full source file (written in Python) and further explanation

Explanation:

This line imports math module

import math

This line prompts user for sensor reading

sensorReading = float(input("Sensor Reading: ")

This line prompts user for target value

targetValue = float(input("Target Value: ")

This line compares both inputs

if abs(targetValue - sensorReading) < 0.0001:

   print("Equal") This is executed if both inputs are close enough

else:

   print("Not Equal") This is executed if otherwise

Answer 2

The expression that will cause the following code to print "Equal" if the value of sensorReading is "close enough" to targetValue and print "Not equal" if otherwise is as follows;

sensorReading = float(input("write your sensor reading: "))

targetValue = float(input("write your target value: "))

if abs(sensorReading - targetValue) < 0.0001:

  print("Equal")

else:

  print("not Equal")

The code is written in python.

Code explanation

• The variable sensorReading  is used to store the user's inputted sensor reading.
• The variable targetValue is used to store the user's inputted target value.
• If the difference of the sensorReading and the targetValue is less than 0.0001. Then we print "Equal"
• Otherwise it prints "not Equal"

learn more on python code here; https://brainly.com/question/14634674?referrer=searchResults