Answer:
[tex]x=\sqrt{33}[/tex]
Step-by-step explanation:
We can use the Pythagorean theorem to solve this
in the 11, 13 triangle,
[tex]11^2 + h^2 = 13^2\\121 + h^2 = 169\\h^2 = 48\\h = 4\sqrt{3}[/tex]
to find x
[tex]x^2 + (4\sqrt{3} )^2=9^2\\x^2 + 48 = 81\\x^2 = 33\\x = \sqrt{33}[/tex]
