Question

What is the area of a square whose perimeter is 28x^2 + 4x?

Answer 1

Answer:

Step-by-step explanation:

Divide by 4 to get 1 side

28x^2/4 + 4x/4

7x^2 + 4 = s or one side

Now square that one side

Area = s^2

Area = (7x^2 + 4)^2

Area = 49x^4 + 28x^2 + 28x^2 + 16

Area = 49x^4 + 56x^2 + 16