Question

Mark and Don are planning to sell each of their marble collections at a garage sale. If Don has 8 more than 2 times the number of marbles Mark has, how many does each boy have to sell if the total number of marbles is 68?

Answer 1

Step-by-step explanation:

Don (8+x)

Mark (2x)

Don + Mark = 68

(8+x) + 2x =68

x + 2x = 68-8

3x =60

x =20

Therefore, Don has 28 marbles while Mark has 40 marbles

Answer 2

The amount  that  each boy have to sell if the total number of marbles is 68 is : Don 16  and Mark  52

Let M represent Mark and D represent Don

Hence:

M+D= 68 marbles

M = 68-D

D = 2M+8

D = 2(68-D)+8

D = 136-2D+8

9D = 144

D = 16

Thus:

Don = 16

Mark =68-16= 52

The amount  that  each boy have to sell if the total number of marbles is 68 is : Don 16  and Mark  52

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