Respuesta :
The value of subtraction of two given complex numbers z₁ and z₂ is cos(π) + isin(π).
What are complex numbers?
A complex number is an element of a number system that includes real numbers and a specific element labeled i sometimes known as the imaginary unit, and which obeys the equation i² = 1. Furthermore, every complex number can be written as a + bi, where a and b are both real values.
How to solve this problem?
We know that cos(π - x) = - cosx, sin(π - x) = sinx, cos(π/4) = 1/√2 = sin(π/4), cos(π/2) = 0, sin(π/2) = 1, cos(π) = - 1, sin(π) = 0.
Given that z₁ = √2[cos(3π/4) + isin(3π/4)] = √2[cos(π - π/4) + sin(π - π/4)] = √2[- cos(π/4) + sin(π/4)] = √2[- 1/√2 + 1/√2] = √2[0] = 0
and z₂ = cos(π/2) + isin(π/2) = 0 + i × 1 = 1
Now, z₁ - z₂ = 0 - 1 = - 1 = - 1 + i × 0 = cos(π) + isin(π)
Therefore, the value of subtraction of two given complex numbers z₁ and z₂ is cos(π) + isin(π).
Learn more about complex numbers here -
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