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The dimensions of the box below are reduced by half. What is the constant of proportionality between the volume of the new box and the volume of the original box? Alternative text A.1/2 B.1/4 C.1/8 D.1/16

The dimensions of the box below are reduced by half What is the constant of proportionality between the volume of the new box and the volume of the original box class=

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Answer:

C. 1/8

Step-by-step explanation:

Dimensions of the Original Box:

Length = 40 inches

Width = 20 inches

Height = 8 inches

Volume of original box = L*W*H = 40*20*8 = 6,400 in³

Dimensions of the New Box (½ of the dimensions of the original box):

Length = ½*40 = 20 in

Width = ½*20 = 10 in

Height = ½*8 = 4 in

Volume of original box = L*W*H = 20*10*4 = 800 in³

Constant of proportionality between the volume of the new box and the volume of the original box = [tex] \frac{800}{6,400} = \frac{1}{8} [/tex]

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