Answer:
The correct option is C
Explanation:
From the question we are told that
The speed of the ball in the horizontal direction is [tex]v = 40 m/s[/tex]
The height from which the ball is thrown is s = 2 m
Generally from kinematic equation
[tex]s = ut + \frac{1}{2} gt^2[/tex]
Here u is the initial velocity of the ball and this zero given that the ball was at rest before it was thrown.
So
[tex]2 = 0 * t + \frac{1}{2} 9.8t^2[/tex]
=> [tex]t = 0.6889 \ s[/tex]
Generally the distance the ball will travel before touching the ground is
[tex]d = v * t[/tex]
=> [tex]d = 40 * 0.6389[/tex]
=> [tex]d = 25.56 \ m[/tex]
