Question

The mean cost to repair the smoke and fire damage that results from home fires of all causes is $11,389 (HomeAdvisor website, December 2014). How does the damage that results from home fires caused by careless use of tobacco compare? The DATAfile named TobaccoFires provides the cost to repair smoke and fire damage associated with a sample of 55 fires caused by careless use of tobacco products. Using past years' data, the population standard deviation can be assumed known with σ = $3,027.

Answer 1

Answer:

The alternative is characterized in the interpretation section following the table, as per the case mentioned.

Step-by-step explanation:

According to the question:

The sample mean will be:

⇒ $\bar{x}=\frac{\Sigma x}{n}$

      $=\frac{1050500}{55}$

      $=19100$

The critical value of z ($z_e=1.96$) seems to be the 95 % confidence interval. So the required confidence interval will be:

=  $\bar{x} \ \pm \ x_{critical}\frac{\sigma}{\sqrt{n} }$

= $19100 \ \pm \ 1.96.\frac{3027}{\sqrt{25} }$

= $19100 \ \pm \ 800$

• Consequently, the average cost of repairing flames and smoke injury can outcomes from household fires started by careless tobacco is therefore estimated at quite a 95 percent confidence interval ($18300, $19900).
• The 95 percent confidence interval indicates that the average estimated price of fires results through the use of tobacco is somewhat more costly than that of the average cost of flames results from across all factors that cause.

Answer 2

The 95% confidence interval is ($18300 , $19900) and according to the confidence interval, the average estimated price of fires results through the use of tobacco is somewhat more costly than that of the average cost of flames results from across all factors that cause.

Given :

• The mean cost to repair the smoke and fire damage that results from home fires of all causes is $11,389.
• Sample size, n = 55.
• The population standard deviation can be assumed known with σ = $3,027.

First, find the sample mean by using the following formula:

$\rm \bar{x}=\dfrac{\sum x}{n}$

$\rm \bar{x}=\dfrac{1050500}{55}$

$\rm \bar {x} = 19100$

Now, for 95% confidence level, the confidence interval will be:

$= \rm \bar{x} \pm x_{critical} \dfrac{\sigma}{\sqrt{n} }$

$\rm = 19100\pm 1.96\times \dfrac{3027}{\sqrt{55} }$

$=19100\pm 800$

The 95% confidence interval is ($18300 , $19900).

According to the confidence interval, the average estimated price of fires results through the use of tobacco is somewhat more costly than that of the average cost of flames results from across all factors that cause.

For more information, refer to the link given below:

https://brainly.com/question/20747890