Answer:
The distance from John's house to Bill's house is 5 units
Step-by-step explanation:
John's house is located at the point (-5,7) and Bill's house is located at (-2,3) in a map of the town of Springville.
We need to find the distance from John's house to Bill's house. We use the formula of the distance between two points:
Given two points A(x,y) and B(w,z), the distance between them is:
[tex]d=\sqrt{(w-x)^2+(z-y)^2}[/tex]
Applying the formula:
[tex]d=\sqrt{(-2+5)^2+(3-7)^2}[/tex]
[tex]d=\sqrt{3^2+4^2}[/tex]
[tex]d=\sqrt{9+16}=\sqrt{25}[/tex]
d=5
The distance from John's house to Bill's house is 5 units