Question

1. A ball is dropped from the top of a cliff that is 38 meters tall. Calculate
the ball's impact velocity.
20 points
O +744.8
+27.29
+372.4
+19.30

Answer 1

Answer:

+27.29

Explanation:

To solve this problem we must use the following equation of kinematics.

$v_{f}^{2} =v_{o}^{2}+2*g*x$

where:

Vf = final velocity [m/s]

Vo = initial velocity = 0 ( the ball is dropped)

g = gravity acceleration = 9.81 [m/s²]

x = distance = 38 [m]

Vf² = 0 + (2*9.81*38)

$v_{f}=\sqrt{2*9.81*38} \\ v_{f} = 27.3 [m/s]$