Question

A type of elevator called a cage is used to raise and lower miners in a mine
shaft. Suppose the cage carries a group of miners down the shaft. If the
unbalanced force on the cage is 60.0 N, and the mass of the loaded cage is
1.50 x 10²kg, what is the acceleration of the cage?

Answer 1

Answer:

Acceleration, a = 0.04 m/s²

Explanation:

Given the following data;

Force = 60N

Mass = 1500kg

Force is given by the multiplication of mass and acceleration.

Mathematically, Force is;

$F = ma$

Where;

F represents force.

m represents the mass of an object.

a represents acceleration.

Making acceleration (a) the subject, we have;

$Acceleration (a) = \frac{F}{m}$

Substituting into the equation;

$Acceleration (a) = \frac{60}{1500}$

Acceleration, a = 0.04 m/s²