Respuesta :

nev389
First, we need to determine the slope of the line. The slope can be found by using the formula:
m
=
y
2

y
1
x
2

x
1
Where
m
is the slope and (
x
1
,
y
1
) and (
x
2
,
y
2
) are the two points on the line.
Substituting the values from the points in the problem gives:
m
=
6

0
0


2
=
6

0
0
+
2
=
6
2
=
3
The point
(
0
,
6
)
is also the
y
intercept. Therefore we can use the slope-intercept formula to find an equation for the line. The slope-intercept form of a linear equation is:
y
=
m
x
+
b
Where
m
is the slope and
b
is the y-intercept value.
Substituting the slope we calculated and the y-intercept gives:
y
=
3
x
+
6

The linear equation that is solved by both (-6,2) and (0,-4) is y = -x - 4

Using the slope intercept formula for linear equation,

  • y = mx + b

where

m = slope

b = y-intercept

Therefore, lets find m

(-6,2) and (0,-4)

m = -4 - 2 / 0 - (-6) = -6 / 6 = - 1

Lets find b using (0,-4)

y = mx + b

-4 = -1(0) + b

b = -4

There the linear equation in slope intercept form will be as follows

  • y = -x - 4

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