Question

A big dog B and a small dog S are pulling horizontally in opposite directions on a large bone. The bone’s mass is mmm, the big dog’s leftward force magnitude is F_BF
B
​
F, start subscript, B, end subscript and the small dog’s rightward force magnitude is F_SF
S
​
F, start subscript, S, end subscript. The bone accelerates to the right along the table with no friction.

Answer 1

Answer:

m=Fs-Fb/a

Explanation:

khan academy

Answer 2

The correct expression for the mass m of the bone is m=Fs-Fb/a.

What is force?

The force is defined as the shear stress or pressure applied per unit area.

A big dog B and a small dog S are pulling horizontally in opposite directions on a large bone. The bone’s mass is m, the big dog’s leftward force magnitude is Fb and the small dog’s rightward force magnitude is Fs. The bone accelerates to the right along the table with no friction.

Across the bottom is green grass. In the center, there is a brown table with a large bone on top. To the left is a black outline of a large dog facing rightwards that is pulling leftwards on the bone. To the right is a black outline of a small dog facing leftwards that is pulling rightwards on the bone. The small dog stands on a grey box. Across the bottom is green grass.

Two dogs pulling on a large bone. Big dog and small dog images courtesy of pixabay. Consider rightward as the positive direction.

The net force acting on bone will be

F = Fs -Fb

From the Newton's second law of motion, Force  = mass x acceleration

F = ma

m = F/a

m = Fs-Fb/a

Thus, correct expression for the mass m of the bone is m=Fs-Fb/a.

Learn more about force.

https://brainly.com/question/21763500

#SPJ5