Question

A 2nd baseman throws a baseball toward the 1st baseman 60 feet away. The path of the ball is given by f(x)=-0.004x^2+0.3x+6, where f(x) is the height of the ball (in feet) and x is the horizontal distance from the 2nd baseman (in feet). The 1st baseman can reach 8 ft high. Can the 1st baseman catch the ball without jumping?

Answer 1

Answer:

The 1st baseman can't catch the ball without jumping.

Step-by-step explanation:

To know if the 1st baseman can catch the ball without jumping we need to find the height reached by the baseball by solving the following equation:

$f(x) = -0.004x^{2} + 0.3x + 6$

We know that x (the horizontal distance) = 60 feet, so we have:

$f(60) = -0.004(60)^{2} + 0.3(60) + 6$

$f(60) = 9.6 ft$

Since the 1st baseman can reach 8 ft high and the height reached by the baseball is 9.6 ft, the 1st baseman can't catch the ball without jumping.

Therefore, the 1st baseman can't catch the ball without jumping.

I hope it helps you!