We have that the normal force acting on a mountain goat that weighs 550 N and is standing on such a slope is
N=275N
From the question we are told
- Mountain goats can easily scale slopes angled at 60∘ from horizontal.
- What is the normal force acting on a mountain goat that weighs 550 N and is standing on such a slope?
Generally the equation for the normal force acting on a mountain goat is mathematically given as
N=mgcos
N=550*cos60
N=275N
Therefore
The normal force acting on a mountain goat that weighs 550 N and is standing on such a slope is
N=275N
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