Question

Use the balanced chemical equation to calculate the grams of HF that need to react with 4.44 g of SnF2. Express the mass in grams to three significant figures.

Answer 1

Answer:

Explanation:

SnF₂ + 2HF = H₂Sn + 4F

mol weight of SnF₂ = 156.7

mol weight of HF = 20

156.7 gram of SnF₂ reacts with 40 grams of HF

4.44 gram of SnF₂ reacts with 40 x 4.44 / 156.7 grams of HF

= 1.13 grams of HF .