Answer:
v = 38.34 m
Explanation:
Given that,
Mass of a skier, m = 75 kg
It falls down a 75.0 m high slope without friction, h = 75 m
We need to find the velocity of the skier at the bottom of the slope. It is based on the concept of conservation of energy. So, v is the required velocity. So,
[tex]mgh=\dfrac{1}{2}mv^2\\\\v=\sqrt{2gh} \\\\v=\sqrt{2\times 9.8\times 75} \\\\v=38.34\ m/s[/tex]
So, the velocity of the skier at the bottom of the slope is 38.34 m.