Question

A 75.0 kg skier slides down a 75.0 m high slope without friction. The velocity of the skier at the bottom of the slope is

Answer 1

Answer:

v = 38.34 m

Explanation:

Given that,

Mass of a skier, m = 75 kg

It falls down a 75.0 m high slope without friction, h = 75 m

We need to find the velocity of the skier at the bottom of the slope. It is based on the concept of conservation of energy. So, v is the required velocity. So,

$mgh=\dfrac{1}{2}mv^2\\\\v=\sqrt{2gh} \\\\v=\sqrt{2\times 9.8\times 75} \\\\v=38.34\ m/s$

So, the velocity of the skier at the bottom of the slope is 38.34 m.