Question

The speed of a 4.0-N hockey puck, sliding across a level ice surface, decreases at the rate of 2 m/s 2. The coefficient of kinetic friction between the puck and ice is:

Answer 1

Answer:

μ = 0.2041

Explanation:

Given

$a = -2m/s^2$

Required

Determine the coefficient of friction (μ)

The acceleration is negative because it is decreasing.

Solving further, we have that:

$F_f =$ μmg

Where

μ = Coefficient of kinetic friction

$F_f = ma$

So, we have:

ma = μmg

Divide both sides by m

a = μg

Substitute values for a and g

2 = μ * 9.8

Solve for μ

μ = 2/9.8

μ = 0.2041