Answer:
6.62 g of carbon.
Explanation:
We'll begin by calculating the molar mass of C6H12O6. This is illustrated below:
Molar mass of C6H12O6 = (12×6) + (12×1) + (16×6)
= 72 + 12 + 96
= 180 g/mol
Next, we shall determine the mass of carbon (C) in 1 mole (i.e 180 g) of C6H12O6. This is illustrated:
Mass of C in C6H12O6 = 6C = 12×6
Mass of C in C6H12O6 = 72 g
Thus, 180 g of glucose contains 72 g of carbon.
Finally, we shall determine the mass of carbon in 16.55 g of glucose. This can be obtained as follow:
180 g of glucose contains 72 g of carbon.
Therefore, 16.55 g of glucose will contain = (16.55 × 72)/180 = 6.62 g of carbon.
Thus, 16.55 g of glucose contains 6.62 g of carbon.
