Question

The expression (Ux²+x-T) (2x-1) can be written in the form (2x-1)²(x+S) where U, T and S are constant. Find the values of U, T and S....... Please help me solve this polynomial ​

Answer 1

Answer:

U=2, S=1, T=1

Step-by-step explanation:

(Ux²+x-T) (2x-1)=(2x-1)²(x+S)

(Ux²+x-T)=(2x-1)(x+S)=2x²+(2S-1)x-S

U=2

2S-1=1 --> S=1

T=S=1