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Help asappp , What is the slope of a line perpendicular to the line whose equation is
3x + 6y = –18. Fully reduced

Help asappp What is the slope of a line perpendicular to the line whose equation is 3x 6y 18 Fully reduced class=

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Slope = 2

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Answer:

2

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Given

3x + 6y = - 18 ( subtract 3x from both sides )

6y = - 3x - 18 ( divide all terms by 6 )

y = - [tex]\frac{1}{2}[/tex] x - 3 ← in slope- intercept form

with slope m = - [tex]\frac{1}{2}[/tex]

Given a line with slope m then the slope of a line perpendicular to it is

[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{-\frac{1}{2} }[/tex] = 2

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