Question

An astronaut on the surface of Mars standing on the edge of a 73.3 meter tall cliff throws a golf ball
down with an initial speed of 4.5 m/s. The ball hits the ground 5.2 seconds later. Find the
acceleration due to gravity on Mars.

Answer 1

Answer:

3.69m/s²

Explanation:

Using the formula;

S = ut + 1/2gt²

Where;

S = distance (m)

u = initial velocity (m/s)

t = time (s)

g = accelerate due to gravity (m/s)

Based on the information provided, S = 73.3m, u = 4.5m/s, t = 5.2s, g= ?

73.3 = (4.5 × 5.2) + 1/2 (g × 5.2²)

73.3 = 23.4 + 1/2 (27.04g)

73.3 = 23.4 + 13.52g

73.3 - 23.4 = 13.52g

49.9 = 13.52g

g = 49.9/13.52

g = 3.6908

g = 3.69m/s²