Question

find the vertex of the parabola whose equation is y = x2 - 4x 6.

Answer 1

y = x^2 - 4x + 6 = x^2 - 4x + 4 + 6 - 4 = (x - 2)^2 + 2
The vertex of a parabola given by y = a(x - h)^2 + k is (h, k).

Therefore, the vertex of y =  (x - 2)^2 + 2 is (2, 2)