Chemistry:
A sample of helium occupies 1820 mL at 719 mmHg. Assume that the temperature is held constant and determine (a) the volume of the helium at 752 mmHg and (b) the pressure, in mmHg, if the volume is changed to 345 mL

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Answer:

You can use the Boyles Law formula

P1V1 = P2V2

Substitute what you have and solve for the new volume. There is no need to do any conversions:

730mmHg * V1 = 719mmHg* 1820mL

V1 = 719mmHg* 1820mL  / 730mmHg

V1 = 1792mmHg

The correct answer should have only 2 significant figures: Volume = 1800mL

Explanation:

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