Find the value of x
A.21
B.27
C.31
D.34

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[tex]3x + 1 = 64[/tex]
Subtract sides 1
[tex]3x + 1 - 1 = 64 - 1[/tex]
[tex]3x = 63[/tex]
Divide sides by
[tex] \frac{3}{3} x = \frac{63}{3} \\ [/tex]
[tex]x = 21[/tex]
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Thus the correct answer is (( A )) .
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