Question

Find the lengths of the sides of a triangle with vertices (0,0), (5,0),(5,12)
choices
A.5,12,12
B.5,5,12
C.5,12,5
D.5,12,13

Answer 1

(0,0),(5,0)  we get 5

(5,0),(5,12)  we get 12

3rd side = 13
option D is right 
hope this helps

Answer 2

A ( 0, 0 ) ,  B ( 5, 12 )  , C ( 5, 0 );
AB = √((5-0)² + (12- 0)²) = √(25 + 144 ) = √169 = 13
BC = √((5-5)²+(12 - 0)²) =√144 = 12
AC = √((5-0)² + (0-0)²) = √25 = 5
Answer: 
D ) 5, 12 , 13