Question

3x-2y=3
How do I solve?

Answer 1

3x - 2y = 3   Subtract 3x from both sides
      -2y = -3x + 3   Divide both sides by -2
         y = $\frac{3}{2}$x - $\frac{3}{2}$

Answer 2

3x-2y=3
3x=2y+3 (add 2y to each side)
3x-3=2y (-3 to each side so your focus is on the ys)
$\frac{3x-3}{2}$ = y