Question

Use the square roots property to solve the quadratic equation (6d+1)2+12=13. If there are multiple answers, list them separated by a comma, e.g. 1,2. If there is no solution, enter ∅.

Answer 1

Answer:

$d = 0$

Step-by-step explanation:

Given

$(6d+1)^2+12=13$

Required

Solve for d

$(6d+1)^2+12=13$

Collect Like Terms

$(6d+1)^2=13 - 12$

$(6d+1)^2=1$

Using square roots property

$\sqrt{(6d+1)^2}=\sqrt 1$

$6d+1 = 1$

Collect Like Terms

$6d = 1 - 1$

$6d = 0$

$d = 0/6$

$d = 0$