Question

A gas sample in a Boyle’s law apparatus is compressed to a volume of 22.0 mL. If its original volume was 37.0 mL at 12,000 Pa, what is the new pressure of the gas sample. Show your calculations.

Answer 1

Answer:

The answer is 20,181 Pa

Explanation:

The new pressure can be found by using the formula for Boyle's law which is

$P_1V_1 = P_2V_2$

Since we are finding the new pressure

$P_2 = \frac{P_1V_1}{V_2}$

From the question we have

$P_2 = \frac{37 \times 12000}{22} = \frac{444000}{22} \\ = 20181.81...$

We have the final answer as

20,181 Pa

Hope this helps you