Answer:
-4 ≤ x ≤ 6
Step-by-step explanation:
Given that :
Average January temperature = 1°F
Let actual temperature = x ; which varies 5°F warmer or colder of this temperature ;
|x + average temperature | ≤ 5
x + 1 ≤ ±5
1 - 5 ≤ x ≤ 1 + 5
-4 ≤ x ≤ 6
Lower bound (colder) = 1 - 5 = - 4
Uppwr bound (warmer) = 1 + 5 = 6