Question

PLEASE EXPLAIN HOW YOU GOT ANSWER. A school administrator tells everyone in the building that they will be having a fire drill randomly sometime during the school day which is from 8 a.m. to 3 p.m. If second period is from 9:00 a.m. to 10:00 a.m., what is the probability of the fire drill happening during second period?

Answer 1

Answer:

$Probability = \frac{1}{7}$

Step-by-step explanation:

Given

$School\ Hours = 8am\ to\ 3pm$

$Second\ Period = 9am\ to\ 10am$

Required

Determine the probability that the fire drill happens in the second period

First, we need to convert both time range to hours.

8 am to 3 pm is 7 hours.

So:

$School\ Hours = 7\ hours$

9 am to 10 am is 1 hour.

So:

$Second\ Period = 1\ hour$

The required probability can then be calculated using:

$Probability = \frac{Required\ Events}{Total\ Events}$

In this case, it is:

$Probability = \frac{Second\ Period}{School\ Hours}$

$Probability = \frac{1\ Hour}{7\ Hours}$

$Probability = \frac{1}{7}$

Answer 2

Answer: 14.3%

Step-by-step explanation: 1/7=14.3%